49x^2+147x-96=02

Solution for 49x^2+147x-96=02 equation:

49x^2+147x-96=02

We move all terms to the left:

49x^2+147x-96-(02)=0

We add all the numbers together, and all the variables

49x^2+147x-98=0

a = 49; b = 147; c = -98;
Δ = b2-4ac
Δ = 1472-4·49·(-98)
Δ = 40817
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40817}=\sqrt{2401*17}=\sqrt{2401}*\sqrt{17}=49\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(147)-49\sqrt{17}}{2*49}=\frac{-147-49\sqrt{17}}{98}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(147)+49\sqrt{17}}{2*49}=\frac{-147+49\sqrt{17}}{98}
$